Set Continuous Scroll as Default in Preview
[Solved] Preview changing default fullscreen view option to continuous scroll
- Thread starter randomuser
- Start date
- #1
randomuser Asks: Preview changing default fullscreen view option to continuous scroll
I would like to open preview windows in full screen and I would like to see them in continuous scroll mode as default. I already changed opening for the first time to continuous scroll it works for small preview windows but when I go to full screen mode, it becomes 2 page view which is frustrating and every time I have to do cmd+1. Is there any solution for this? macos monterey 12.3.1
- Sinoi Coutinho
- Biology
- Replies: 0
Sinoi Coutinho Asks: Why are monocots more advanced than dicots , shouldn't more complexity mean more evolved?
Features like pith , endodermis, pericycle , medullary rays and secondary growth are not present is monocots .how are monocots still more advanced?
- Nanoputian
- Chemistry
- Replies: 0
Nanoputian Asks: Is Hydrogen Bonding a Type of Dipole Dipole Interaction?
I understand that dipole dipole forces is due to the attraction of the different partials charges of atoms in different molecules due to their different electro-negativities.
For hydrogen bonding, my understanding of it is that they are just a special case of dipole dipole forces. In certain molecules in where the difference in electro-negativities between the different atoms is high enough, then even stronger dipole dipole forces will be form which are known as hydrogen bonding. For example, in $\ce{H_2O}$ where the difference in electro-negativity of H and O is 1.24, hydrogen bonding occur. This is why hydrogen bonding can only occur between hydrogen and nitrogen, fluorine or oxygen.
However, my school teacher says that hydrogen bonding in fact is not a type of dipole dipole force as she says that hydrogen bonding occurs differently to dipole dipole forces. She said that hydrogen bonding occurs to the attraction of the lone pairs in oxygen, fluorine and nitrogen atoms to atoms with a positive partial charge. Hence this is why hydrogen bonding is much stronger than conventional dipole dipole forces.
But this doesn't make sense because if hydrogen bonding is due to the attraction of H to the lone pair of electrons, shouldn't hydrogen bonding also form between H and Cl or I or any other atom that has a lone pair and is more electronegative than H?
Edit 1
From the comments below, it appears that the actual answer is more complicated than the simple explanation of hydrogen bonding given above. After doing some research, I have became aware of the Advanced Theory of the Hydrogen Bond which states that the hydrogen bond actually contains 10% covalent nature. However none actually explain how they are formed. Could someone please explain how hydrogen bonding actually in reality form.
Edit 2
So in response to the excellent answer by jheindel, is the reason why hydrogen bonding is considered partly covalent in nature is because the let say in water, oxygen's MO partly overlaps with the MO of the hydrogen atom in the other molecule. Also this is why they are much stronger than conventional dipole dipole forces?
- Polarized photon
- Physics
- Replies: 0
Polarized photon Asks: Constructing the QED Lagrangian. $4=3\oplus 1$ vs $4=1\oplus 1\oplus 1\oplus 1$
I am going through Schwartz's "Quantum Field Theory and the Standard Model". When trying to construct the Lagrangian for QED on chapter 8.2.2 his approach is as follows:
We want a theory where the four degrees of freedom of a 4-vector are expressed as three degrees of freedom mixed together plus one extra. This would be $4=3\oplus 1$. I understand why this has to be the case. He then proposes a first attempt at building a Lagrangian as $$\mathcal{L}=-\frac{1}{2}\partial_\nu A_\mu\partial_\mu A_\nu + \frac{1}{2}m^2A_\mu^2$$ From this you can get that the equations of motion are given by $$(\Box + m^2)A_\mu = 0$$ So far so good. But then he states that we can see from this, that this is the Lagrangian for four scalar fields instead of the lagrangian from a massive spin-1 field. So in this case $4=1\oplus 1\oplus 1\oplus 1. $ This is where I get lost. Where can we actually see that from the equation of motion?
He then goes about constructing a better Lagrangian and ends up with $$\mathcal{L}=\frac{a}{2}A_\mu\Box A_\mu + \frac{b}{2}A_\mu\partial_\mu\partial_\nu A_\nu + \frac{1}{2}m^2A_\mu^2$$ which he claims, has the correct property of being $4=3\oplus 1$.
I would like to get some clarity about the way we can know these things from looking at the equation. Thank you in advance.
- user303096
- Social
- Replies: 0
user303096 Asks: Export from Adobe XD to HTML / CSS / JavaScript
Is this possible?
I read on a post in the Adobe forum that there is a plugin called 'Web Export', but it looks like it hasnt been updated since 2019 so I wonder how reliable it is.
I know ideally a website would be coded from scratch, but I don't have much enthusiasm for that these days
- sigalor
- Social
- Replies: 0
sigalor Asks: Workflow for embedding corporate-looking 3D models into presentation slides
I have recently discovered Pitch and on their website https://pitch.com they are using a lot of 3D assets blended into the 2D slide designs. I've seen this style of corporate design at several other brands before, but as I am still quite new to 3D design, I do not really know what to even search for to be able to reproduce this style. Some questions:
- The 3D models seem quite simple (rounded corners and comparably low-poly and/or simple geometry), whereas many 3D model assets I find elsewhere on the internet are too detailed. What are some websites or 3D model databases where I can find models that are shaped similarly to the ones shown below?
- The shading and the shadows are also quite particular and I quite like this style. How can this shading be achieved with 3D modeling software?
- From a workflow perspective, I feel like using a very versatile software like Blender seems a bit overkill and inflexible. When embedding a rendered 3D model into a presentation, I would need to model it in Blender first (i.e. also adjust all the shading, lighting, camera position and colors manually), then export a PNG and finally add this PNG to the presentation slides. Instead of being this static and tedious, I'd like the process of embedding 3D imagery into a presentation to be very dynamic, fast and responsive. Is there any software which makes this easier, i.e. essentially a combination of PowerPoint/Google Presentations and a very simplified version of Blender?
- Mee Na
- Mathematics
- Replies: 0
Mee Na Asks: Application of Holder Inequality
Let $p>0$ how can I get the inequality below by applying Holder inequality \begin{equation} \int_{\Omega}|u|^{p}v|v|^{2}dx\leq \Vert u\Vert_{2}.\Vert v\Vert_{2} \end{equation}
- user0735
- Mathematics
- Replies: 0
user0735 Asks: Inequality between probabilities
Consider $x_{s}$ which is a random variable from a standard normal distribution, and given values $w_{s}>0$ for $s=1,2,...,r,$ where $r$ is some finite number. We have that $$(\sum_{s=1}^rw_{s}x_{s}^2)\geq(w_{min}\sum_{s=1}^rx_{s}^2)$$ where $w_{min}=min_{s}(w_{s})$.
What inequality holds between the probabilities $Pr(\sum_{s=1}^rw_{s}x_{s}^2>c)$ and $Pr(w_{min}\sum_{s=1}^rx_{s}^2>c),$ where $c$ is a positive given value?
Source: https://solveforum.com/forums/threads/solved-preview-changing-default-fullscreen-view-option-to-continuous-scroll.776987/
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